X^2+0.46x=0

Solution for X^2+0.46x=0 equation:

X^2+0.46X=0

a = 1; b = 0.46; c = 0;
Δ = b2-4ac
Δ = 0.462-4·1·0
Δ = 0.2116
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.46)-\sqrt{0.2116}}{2*1}=\frac{-0.46-\sqrt{0.2116}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.46)+\sqrt{0.2116}}{2*1}=\frac{-0.46+\sqrt{0.2116}}{2}
$